Given the following data for the reaction below, which is the correct rate law? CH4(g) + O₂(g) → CO₂(g) + 2H₂O(g) -> [0₂
Posted: Fri May 06, 2022 7:50 am
Given the following data for the reaction below, which is the correct rate law? CH4(g) + O₂(g) → CO₂(g) + 2H₂O(g) -> [0₂lo. M [CH4], M Initial Rate, M/min Experiment 01 2.33x10-4 3.24x10-4 2.0x10-6 Experiment 02 2.33x10-4 6.48x10-4 8.0x10-6 Experiment 03 4.66x10-4 6.48x10-4 8.0x10-6
Oa) Rate = k[CH41² b) Rate = K[0₂]² c) Rate = K[CH4]² [0₂] d) Rate = K[CH4]²[02]² e) Rate = k[CH4] [0₂]²
Oa) Rate = k[CH41² b) Rate = K[0₂]² c) Rate = K[CH4]² [0₂] d) Rate = K[CH4]²[02]² e) Rate = k[CH4] [0₂]²