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Calculate the potential developed by a voltaic cell using the following reaction if all dissolved species are 0.012 M at
Posted: Fri May 06, 2022 7:43 am
by answerhappygod
- Calculate The Potential Developed By A Voltaic Cell Using The Following Reaction If All Dissolved Species Are 0 012 M At 1 (27.52 KiB) Viewed 24 times
Calculate the potential developed by a voltaic cell using the following reaction if all dissolved species are 0.012 M at 25 °C. 2 Fe²+ (aq) + H₂O₂(aq) + 2 H+ (aq)-2 Fe³+ (aq) + 2 H₂O(1) Acidic Solution H₂O.(aq) + 2 H(aq) +202 H₂O(l) Standard Electrode Potential, E (volts) +1.77 Au!(00) + Au(1) +1.68 Au(aq) + 3 e → Au(s) +1.50 Bra(t)+2 e 2 Br(aq) +1.08 NOx (aq) + 4 H(aq) + 3 e-NO(g) + 2 H₂O +0.96 Ag (aq) + e-Ag(s) +0.80 +0.789 Hg (aq) + 2a-2 Hg(t) Fe(aq) + Fe (aq) +0.77 Cu³(aq) +2 e → Cu(s) +0.337 Hg.Cl(s) +2e-2 Hg(t) + 2 CH(aq) +0.27 Sn (aq) + 2e Sn**(aq) +0.15 2 H(aq) +2e-H:(g) 0.00 -0.126 -0.14 Pb (aq) 2e-Pb(s) Sn²(aq) +2e-Sn(s) N²2 (aq) +2 e →Ni(s) -0.25 -0.40 Cd(s) Cd (aq) +2 e Cr(aq) + -0.408 Cr²³(aq) -0.44 Fe(aq) +2 e-> Fe(s) -0.763 Zn(aq) +2 e → Zn(s) -0.91 Cr²³(aq) + 2 e →Cr(s) -1.66 AP (aq) + 3 e →Al(s) -2.37 Mg(aq) +2 e-Mg(s)