Answer Happy

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40ml of HCl in the 500mL beaker. But only pour 5ml of HCl solution in a buret for every titration
Molarity of your own NaOH Solution (4 points): 0.300M NaOH to make 500ML Original NaOH solution 1. Grams of NaOH calculated to make 250 mL of the original NaOH solution (5 points): •3M =.3 moles 250 ml 7.25L 2 12 • 3 mol x-25l = 075 moles Naol IL .075 moves NaOH X 40g = 3g NaOH Imore 2. Calculate the volume of the HCI solution (for each trial) that is required to reach the equivalence po assigned NaOH solution. (8 points) •075 moles NaOH x 40g здраон Imole Na 1x 22.99 0 - 1x16 H - 1/X 11008 Revised 03/2021 39.999/mol or 40 g/mol T

3. Complete the table with the values from the first titration. Don't forget to have proper Sig. Figs, and units. (2 points each space) Titration 1 Titration 2 Volume of NaOH SO Initial Buret Reading (HCI) 33 Final Buret Reading (HCI) 29 41.3 Total Volume of HCI added 29 8.3 4. Concentration of the original NaOH solution determined by the titration (4 points): Diluted NaOH solution 5. What is the volume of NaOH solution needed to make a 1/5 dilution of the 250 mL of the original NaOH solution (8 points): 6. Calculate the volume of the HCI solution (for each trial) is required to reach the equivalence point with of your assigned NaOH solution. (8 points) 9 250 ml 0

7. Complete the table with the values from the second titration. Don't forget to have proper Sig. F (2 points each space) Titration 3 Titration 4 Volume of NaOH 40 Initial Buret Reading (HCI) 13 19 Final Buret Reading (HCI) 14.5 23 Total Volume of HCI added 1.5. 4 8. Concentration of the diluted NaOH solution determined by the titration: (8 points) 10