Answer Happy

Aluminum sulfate has many uses in industry. It can be prepared by reacting aluminum hydroxide and sulfuric acid: 2Al(OH)3 + 3H₂SO4 → Al2(SO4)3 + 6H₂O (a) When 44.3 g of Al(OH)3 and 44.3 g of H₂SO4 are reacted, how many moles of Al2(SO4)3 can be produced? mol Al2(SO4)3 Which substance is the limiting reactant? (b) When 53.5 g of H₂SO4 and 33.5 g of Al(OH)3 are reacted, how many grams of Al2(SO4)3 are produced? g Al2(SO4)3 i Which reactant is in excess? (c) In a reaction vessel, 2.6 mol of Al(OH)3 and 5.7 mol of H₂SO4 react. Determine which substances, and their molar quantities, will be present the container when the reaction goes to completion. Products: Al2(SO4)3, H₂O H₂SO4: Moles of Al2(SO4)3 in container: i mol Moles of H₂O in container: Moles of excess reactant in container: i mol mol