Answer Happy

Activity 4: Impulse -- Momentum Theorem in an Inelastic Collision It is also possible to examine the impulse-momentum theorem in a collision where the cart sticks to the clay and comes to rest atter the collision. This can be done by replacing the spring with some clay, and attaching a hook to the end of the force probe. You will need extra equipment x large blob of clay (about 5 grams) x bumper stop Remove the extra mass from your cart so that its mass is the same as in Activity 2. Replace the spring with a hook attachment screw (which is meant to stick in the clay instead of bouncing off. Put the stopper on the cart in order to keep the mass unchanged from its value in Activity 2 Remove the springy part of the bracket and amach the clay directly to the bumper, as shown in the following diagram. The rest of the setup is as in Activity 2. You can use the same experiment file as in Activity 2. Prediction: Now when the cart hits the bumper it will come to rest stuck to the clay. What do you predict about the impulse? Will it be the same, larger, or smaller than in the nearly elastic collision? What do you predict now about the impulse and momentum? Will they equal each other, or will one be larger than the other? direction of motion force probe bumper play dough 0.75m positive direction Zero the force probe, and then collide the cart with the clay Try several times until you get the initial velocity about the same as in Activity 2. Be sure to re-form the clay in between nuns. Find the average velocity, as in Activity 2, and calculate the change in momentum. Average velocity toward the bumper 21 (m/s) p=_ (kg mis) Find the impulse as in Activity 2. Print your graphs and afflix them to your lab report 3-0.07 kgm/s motion sensor 0.15 m
Question 8: Compare the force- time curve for the inelastic collision to that for the nearly elastic collision. How are the curves similar? How are they different? Question 9: Were the impulse and change in momentum equal to each other for the inelastic collision? Explain why you think the results came out the way they did. Question 10: Do you think that the momentum change is equal to the impulse for all collisions? Justify your answer.
Force N 2 Velocity ins) 2.0 15 10 0.5 0.0 -0.5 -- 3333333333 04 02 0.0 02 -04 0.8 -1.0 Mar 0:00 38 Mean 0.00 4 Graphtide here] 1.9 1.11 40 41 42 4) ANNIE XL D 4.350 Ne: 0.07 NS 45 46 Time is Q Time s 47 48 Area 0.00 ms S 50 2 3.1 M 5.3 1 Run +1 Run #1 . V 10