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A1. We have a 0.6 kg (3 mol) sample of solid mercury initially in thermal equilibrium with liquid nitrogen at T = 77 K.
Posted: Fri May 06, 2022 6:38 am
by answerhappygod
- A1 We Have A 0 6 Kg 3 Mol Sample Of Solid Mercury Initially In Thermal Equilibrium With Liquid Nitrogen At T 77 K 1 (41.4 KiB) Viewed 30 times
A1. We have a 0.6 kg (3 mol) sample of solid mercury initially in thermal equilibrium with liquid nitrogen at T = 77 K. We then move it to our oven to add heat and turn it into a vapor. a) Given the specific heat of mercury is 139.9 J/(kg K). How much energy is required to heat it up to its melting point at 234.3 K. b) If mercury's latent heat of fusion is 11,450 J/kg. how much energy is needed to liquefy our sample. c) Now we will increase the temperature from 234.3 K to its boiling point at 630 K. Calculate the energy using the specific heat from part a). d) The latent heat of vaporization is 2.95 x 106 J/kg for mercury. Calculate the energy needed to transform the mercury into a gas. e) What is the total heat (add up your answers from parts a-d)?