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Question 1 (1 point) The table below summarizes the IQ summary of 2 groups Group 1 control and Group 2 given a pill before the test. (We will assume equal variance) -mean- -standard deviation- -n- Group 1 95 13 13 Group 2 105 16 16 Find a 99% Cl for the true mean IQ difference between group 1 and group 2 What was the Point estimate used? 200 95 O-10 105
Question 2 (1 point) The table below summarizes the IQ summary of 2 groups Group 1 control and Group 2 given a pill before the test. (We will assume equal variance) -mean- -n- -standard deviation- 13 Group 1 95 13 Group 2 105 16 16 When testing at alpha= 1%, if the true mean IQ of group 1 is lower than group 2 The Test Statistic is: round to 2 d.p. 2
Question 3 (1 point) The table below summarizes the IQ summary of 2 groups Group 1 control and Group 2 given a pill before the test. (We will assume equal variance) -mean- -standard deviation- -n- Group 1 95 13 13 Group 2 105 16 16 When testing at alpha = 1%, if the true mean IQ of group 1 is lower than group 2 The Critical Value used to determine the rejection region is: 02.771 O-2.473 both -2.771 and 2.771 both -2.473 and 2.473
Question 5 (1 point) The table below summarizes the daily income of 2 stores. Assume unequal variances. -mean- -standard deviation--n- Store A 665 60 6 Store B 556 170 17. Test at alpha = 10% if the true average of store A is different from the average of store B. What is the Null hypothesis? Ο ΝΑ > Β Ο μα * μΒ μA <μB uA = uB
Question 6 (1 point) The table below summarizes the daily income of 2 stores. Assume unequal variances. -mean- -standard deviation- -n- Store A 665 60 6 Store B 556 170 17 Test at alpha = 10% if the true average of store A is different from the average of store B. What is the degrees of freedom for the Critical Value? 19 22 21 20
Question 7 (1 point) The table below summarizes the daily income of 2 stores. Assume unequal variances. -mean- -standard deviation--n- Store A 665 60 6 Store B 556 170 17 Test at alpha = 10% if the true average of store A is different from the average of store B. What is the Standard Error? round to 2 d.p. A/
Rhode Island legalized medical marijuana in 2006. In 2014, a poll was conducted among 400 college-age Rhode Island residents (1) and it was found that 100 supported the legalization of recreational marijuana. And among 500 college-age Massachusetts residents (2) it was found that 150 supported the legalization of recreational marijuana. Using a 1% significance level, perform an appropriate test of hypothesis to test if the proportion of college-age Massachusetts residents who support the legalization differs from the proportion of college-age Rhode Island residents who support the legalization of recreational marijuana. The alternative hypothesis is Op1 < p2 Op1 > p2 Op1 * p2 Op1=p2
Rhode Island legalized medical marijuana in 2006. In 2014, a poll was conducted among 400 college-age Rhode Island residents (1) and it was found that 100 supported the legalization of recreational marijuana. And among 500 college-age Massachusetts residents (2) it was found that 150 supported the legalization of recreational marijuana. Using a 1% significance level, perform an appropriate test of hypothesis to test if the proportion of college-age Massachusetts residents who support the legalization differs from the proportion of college-age Rhode Island residents who support the legalization of recreational marijuana. The Test Statistic for this test is? -2.304 -2.45 -1.66 -1.567
Rhode Island legalized medical marijuana in 2006. In 2014, a poll was conducted among 400 college-age Rhode Island residents (1) and it was found that 100 supported the legalization of recreational marijuana. And among 500 college-age Massachusetts residents (2) it was found that 150 supported the legalization of recreational marijuana. Using a 1% significance level, perform an appropriate test of hypothesis to test if the proportion of college-age Massachusetts residents who support the legalization differs from the proportion of college-age Rhode Island residents who support the legalization of recreational marijuana. The p-value for this test is? 0.0465 0.9535 0.907 0.097
Question 11 (1 point) Rhode Island legalized medical marijuana in 2006. In 2014, a poll was conducted among 400 college-age Rhode Island residents (1) and it was found that 100 supported the legalization of recreational marijuana. And among 500 college-age Massachusetts (2) residents it was found that 150 supported the legalization of recreational marijuana. Using a 1% significance level, perform an appropriate test of hypothesis to test if the proportion of college-age Massachusetts residents who support the legalization differs from the proportion of college-age Rhode Island residents who support the legalization of recreational marijuana. What type of error could have occurred? Type III Type II Type I
The table below shows the summary for weights of 9 people before a diet program and after. The weight lost by each person was also recorded and summarized in the table below. -mean- -standard deviation- Before 208.71 15.117 After 201.71 15.273 Weight loss 7 7.785 Test at alpha = 5% if the weights loss program works. The alternative hypothesis is μd * 0 μd > 0 μd = 0 μd < 0
The table below shows the summary for weights of 9 people before a diet program and after. The weight lost by each person was also recorded and summarized in the table below. -mean- -standard deviation- Before 208.71 15.117 After 201.71 15.273 Weight loss 7 7.785 Test at alpha = 5% if the weights loss program works. The Critical Value used is: 1.86 1.645 1.96 1.83
Question 14 (1 point) The table below shows the summary for weights of 9 people before a diet program and after. The weight lost by each person was also recorded and summarized in the table below. -mean- -standard deviation- Before 208.71 15.117 After 201.71 15.273 Weight loss 7 7.785 Test at alpha= 5% if the weights loss program works. The Test Statistic is: round to 1 d.p. A/
Question 15 (1 point) The table below shows the summary for weights of 9 people before a diet program and after. The weight lost by each person was also recorded and summarized in the table below. -mean- -standard deviation- Before 208.71 15.117 After 201.71 15.273 Weight loss 7 7.785 Test at alpha = 5% if the weights loss program works. The conclusion is: At alpha = 5% the program works. At alpha = 5% the program does not works.
Question 16 (1 point) The table below summarizes the IQ summary of 2 groups Group 1 control and Group 2 given a pill before the test. (We will assume equal variance) -mean- -standard deviation- -n- Group 1 95 13 13 Group 2 105 16 16 Find a 99% CI for the true mean IQ difference between group 1 and group 2 What was the degrees of freedom used? 15 026 27 12