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= Homework: Ass... Question 9, *13.1.9-T Part 3 of 6 HW Score: 90.56%, 9.06 of 10 points O Points: 0.56 of 1 Save A steel pipe company recently developed a new pipe product for a customer. According to specifications, the pipe is supposed to have an average outside diameter of 2.00 inches with a standard deviation equal to 0.10 inch, and the distribution of outside diameters is to be normally distributed. Before going into full-scale production, the company selected a random sample of 30 sections of pipe from the initial test run, as shown in the accompanying table. Complete parts a and below. Click the icon to view the data table. .. State the appropriate null and alternative hypotheses. Choose the correct answer below. A. Ho: The pipe diameter is normally distributed with u = 2.00 and o=0.10. HA: The pipe diameter is not normally distributed with u = 2.00 and o = 0.10. OB. Ho: u = 2.00 HA:u#2.00 C. Ho: #2.00 HA: 4 = 2.00 OD. Ho: The pipe diameter is not normally distributed with u = 2.00 and o=0.10. HA: The pipe diameter is normally distributed with p = 2.00 and o=0.10. Find the observed frequency of each class. Observed Frequency 5 Class Under 1.9 1.9 to under 2.0 2.0 to under 2.1 2.1 and over 12 7 6 The test statistic is x2 = 3.867. (Round to three decimal places as needed.)

= Homework: Ass... Question 9, *13.1.9-T Part 3 of 6 HW Score: 90.56%, 9.06 of 10 points O Points: 0.56 of 1 Save A steel pipe company recently devel 2.00 inches with a standard deviatid the company selected a random sa X an average outside diameter of going into full-scale production, e parts a and below. Data Table ! Click the icon to view the data Full data set State the appropriate null and alter A. Ho: The pipe diameter is no HA: The pipe diameter is ng OB. Ho: u = 2.00 HA: μ#2.00 C. Hou#2.00 HA: 4 = 2.00 Diameter Pipe Section (inches) 2.03 2.13 2.08 1.99 1.89 2.06 2.19 2.01 2.05 10 1.98 11 1.95 12 1.89 13 2.11 14 2.01 15 2.12 Diameter Pipe Section (inches) 16 1.97 17 1.88 18 1.99 19 2.12 20 1.91 21 1.91 22 22 1.95 23 2.18 24 1.94 25 1.94 26 26 2.07 27 1.82 28 1.95 29 1.96 30 1.81 OD. Ho: The pipe diameter is ng HA: The pipe diameter is ng Find the observed frequency of ead Observed Frequency 5 Class Under 1.9 1.9 to under 2.0 2.0 to under 2.1 2.1 and over 12 7 6 Print Done The test statistic is x2 = 3.867. (Round to three decimal places as