Let f: A → R be a continuous function. If E CA is connected, then f(E) is connected. Now, by using this theorem, prove t
Posted: Thu May 05, 2022 7:36 pm
Let f: A → R be a continuous function. If E CA is connected, then f(E) is connected. Now, by using this theorem, prove the Intermediate Value Theorem. Namely, prove that if f [a, b] → R is continuous and LER is such that f(a) < L < f(b) or f(a) > L > f(b), then there exists c = (a, b) such that f(c) = L.
Proof. Intending to use the characterization of connected sets in Theorem 3.4.6, let f(E) = AUB where A and B are disjoint and nonempty. Our goal is to produce a sequence contained in one of these sets that converges to a limit in the other. Let C = {r € E: f(x) = A} and D = {r € E : f(x) € B}. The sets C and D are called the preimages of A and B, respectively. Using the properties of A and B, it is straightforward to check that C and D are nonempty and disjoint and satisfy E = CUD. Now, we are assuming E is a connected set, so by Theorem 3.4.6, there exists a sequence (₁) contained in one of C or D with x = lim ₁ contained in the other. Finally, because f is continuous at x, we get f(x) = lim f(zn). Thus, it follows that f(n) is a convergent sequence contained in either A or B while the limit f(x) is an element the other. With another nod to Theorem 3.4.6, the proof is complete.
Proof. Intending to use the characterization of connected sets in Theorem 3.4.6, let f(E) = AUB where A and B are disjoint and nonempty. Our goal is to produce a sequence contained in one of these sets that converges to a limit in the other. Let C = {r € E: f(x) = A} and D = {r € E : f(x) € B}. The sets C and D are called the preimages of A and B, respectively. Using the properties of A and B, it is straightforward to check that C and D are nonempty and disjoint and satisfy E = CUD. Now, we are assuming E is a connected set, so by Theorem 3.4.6, there exists a sequence (₁) contained in one of C or D with x = lim ₁ contained in the other. Finally, because f is continuous at x, we get f(x) = lim f(zn). Thus, it follows that f(n) is a convergent sequence contained in either A or B while the limit f(x) is an element the other. With another nod to Theorem 3.4.6, the proof is complete.