Objective: to derive this Eq. 2 M²₁ + (y − 1) M²₂2 = 2y (x-1) M²₁-1 = f(y,M₁) < 1.0 From Continuity Eq.(1): PM₁P₂M₂ √T₁
Posted: Thu May 05, 2022 6:24 pm
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Objective: to derive this Eq. 2 M²₁ + (y − 1) M²₂2 = 2y (x-1) M²₁-1 = f(y,M₁) < 1.0
From Continuity Eq.(1): PM₁P₂M₂ √T₁ √√1₂ Y Y From Energy Eq.(2): T(1+1=¹M²) - T₂(1 + 1 = ¹M²) T, 2 From Momentum Eq.(3): (p)(1+yM²) ={P](1+yM²) Step 1: To get rid of P₁ and P2, divide Eq.(1) by Eq.(3) Step 2: To get rid of T₁ and T₂, multiple the Eq from Step 1 by√ √ Eq. (2) [T(1 + 1 = ¹M²) - √ √ T (1+1=¹ M²) = 2 2
Objective: to derive this Eq. 2 M²₁ + (y − 1) M²₂2 = 2y (x-1) M²₁-1 = f(y,M₁) < 1.0
From Continuity Eq.(1): PM₁P₂M₂ √T₁ √√1₂ Y Y From Energy Eq.(2): T(1+1=¹M²) - T₂(1 + 1 = ¹M²) T, 2 From Momentum Eq.(3): (p)(1+yM²) ={P](1+yM²) Step 1: To get rid of P₁ and P2, divide Eq.(1) by Eq.(3) Step 2: To get rid of T₁ and T₂, multiple the Eq from Step 1 by√ √ Eq. (2) [T(1 + 1 = ¹M²) - √ √ T (1+1=¹ M²) = 2 2