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● Pseudo steady-state IPR: Calculate the IPR curves for 0 skin effect but for average reservoir pressure in increments o
Posted: Thu May 05, 2022 5:52 pm
by answerhappygod
- Pseudo Steady State Ipr Calculate The Ipr Curves For 0 Skin Effect But For Average Reservoir Pressure In Increments O 1 (255.38 KiB) Viewed 27 times
● Pseudo steady-state IPR: Calculate the IPR curves for 0 skin effect but for average reservoir pressure in increments of 500 psi from the initial of 5651 to 3500 psi. Drainage radius is 2980 ft. kH = 8.2 md p - Pwf 141.2q Bu 0.472re In kh s) ky = 0.9 md h = 53 ft When average res pressure is 5651 psi,, becomes: Pi = 5651 psi Pb = 1323 psi Co=1.4 x 10-5 Cw = 3 x 10-6 6000 Cf 2.8 x 10-6 5651 - 5q Ct = 1.29 x 10-5 5000 μ = 1.7 cp B 4000 3000 2000 1000 0 psi-1 psi-1 psi-1 psi-1 1.1 res bbl/STB R, 150 SCF/STB 0.19 Sw= 0.34 API° = 28 rw = 0.328 ft (7 7/8 well) Pwt (psi) 0 p=5651 psi 200 5000 4500 4000 3500 400 600 q (STB/d) 5+ 800 1000 1200 Pwf =