Flomash 3 Colculate Iting Thevenia theorem comm Ix L 10522 22 elt (1) Dilsy i (4) = 4 sin (wt + 45°) eH=20√2 sin (evt +
Posted: Thu May 05, 2022 3:10 pm
There are 2 different question on "Homework" page. First question will be solved by using Thevenin theorem.
Second question will be formulated model equations in the same way as on the "Examples" pages.
Flomash 3 Colculate Iting Thevenia theorem comm Ix L 10522 22 elt (1) Dilsy i (4) = 4 sin (wt + 45°) eH=20√2 sin (evt + $0°) L=2H w=1 Forubate model equations for civart Uzz 25 2₂ IS₁₂ = α • U₂₂ I ₁₂ = y • IZ3 (1) 105 [127 Its Z3
Example 2 1 @ d42) V₁ =α• I₂4 Ime 23 Lay 02₂+24 Z4 Juz 23 Z4 Zatis Im3 2+28 10-α-23+04 2₂+ 2yton-24 2 |Z4+25 D -23 24 2 Ed. Izy =dIz E₂ O Imy Imz Ime Im = Es (40) V₁=d-Iz₁ = ( I'm 3 ~ Im²) α²
Exaple stepn I₂₁=OL²I₂₁ 2 %/₁ + ²Y/₂~Y/₂ ~1/₂ √₂ + Yz + ky 0 Y₁ -1₂-24/₂ √₂ +43 +44 -14 0 o |-4₁² Yatys! - 久 a ~Y₁₂.-ß Yu + Y +B U Y И = 1 Laliva I-α. Izy 1 (α IZ₁ B.V 24 I$₁=α• Y₁V₁ I₁=p² (4-₂) 5/8/-3/8/ I I O 0 IIs
Excuple Formulate E( 1 model Iz Z₁ 40€ 23 I'm 15 A Izu equation for Izz 22 Im2 N 3 IES To Im3 zu 3₁ +²30-23 022 23 23+24 17 DE₂ circut Im= Iz₁ = Imi 1₂₂=7m2 Ix₂ = Im² - Im₁ Izy = - Tiny IES= Imi-Imz I₂ = 1m² - 1m² Ima Im2 - E5 E₂ E₂ + E4 11 10 Es Im E₁-E3-Es
Second question will be formulated model equations in the same way as on the "Examples" pages.
Flomash 3 Colculate Iting Thevenia theorem comm Ix L 10522 22 elt (1) Dilsy i (4) = 4 sin (wt + 45°) eH=20√2 sin (evt + $0°) L=2H w=1 Forubate model equations for civart Uzz 25 2₂ IS₁₂ = α • U₂₂ I ₁₂ = y • IZ3 (1) 105 [127 Its Z3
Example 2 1 @ d42) V₁ =α• I₂4 Ime 23 Lay 02₂+24 Z4 Juz 23 Z4 Zatis Im3 2+28 10-α-23+04 2₂+ 2yton-24 2 |Z4+25 D -23 24 2 Ed. Izy =dIz E₂ O Imy Imz Ime Im = Es (40) V₁=d-Iz₁ = ( I'm 3 ~ Im²) α²
Exaple stepn I₂₁=OL²I₂₁ 2 %/₁ + ²Y/₂~Y/₂ ~1/₂ √₂ + Yz + ky 0 Y₁ -1₂-24/₂ √₂ +43 +44 -14 0 o |-4₁² Yatys! - 久 a ~Y₁₂.-ß Yu + Y +B U Y И = 1 Laliva I-α. Izy 1 (α IZ₁ B.V 24 I$₁=α• Y₁V₁ I₁=p² (4-₂) 5/8/-3/8/ I I O 0 IIs
Excuple Formulate E( 1 model Iz Z₁ 40€ 23 I'm 15 A Izu equation for Izz 22 Im2 N 3 IES To Im3 zu 3₁ +²30-23 022 23 23+24 17 DE₂ circut Im= Iz₁ = Imi 1₂₂=7m2 Ix₂ = Im² - Im₁ Izy = - Tiny IES= Imi-Imz I₂ = 1m² - 1m² Ima Im2 - E5 E₂ E₂ + E4 11 10 Es Im E₁-E3-Es