If the DFT of x[n] with period N = 8 is X[k] = {3,4 + 5j, −4 − 3j, 1 + 5j, −4, 1 − 5j, −4+ 3j,4 − 5j}. (a) Find the aver
Posted: Thu May 05, 2022 2:04 pm
Emphasis : please show the steps on obtaining x[n],
thanks
The work below was done by the other people but I'm pretty sure
that there is something odd with the answer (you could also start
with this but please state what's wrong with it)
If the DFT of x[n] with period N = 8 is X[k] = {3,4 + 5j, −4 − 3j, 1 + 5j, −4, 1 − 5j, −4+ 3j,4 − 5j}. (a) Find the average value of x[n] (b) Find the signal power of x[n]. (c) Is x[n] even or odd or neither.
given зат OFT of xmn, N28 x(²) 2 √ 3, 4 +55.-4-35, 1+55, -4,1-55, -4+85, 4-55 4 са, Average value испра 3+4+5j-4-3j +1+5j-4+-s] -4+3j+4-sj g ItJo 8 (11= 0.125
(6) signal power p² = { 1 [~ 111] 1² 2= N 3 2 2 = = [2 (0)² + [51] ² + [5 (²1)² + ((31) ²³ + (5 (41)² + (a(sy) ² + [~ [6₁] ² + [~ (+1]²] 2 2 = & [ 3² + |( 4 +5√ √ √(- 4 - 3 5 ) 1³² + |(1 + 5√² ) ² + (-4/²) + | 11-5; }} +1 (4 + 3√11² +K4-sjj1|² ] 2 3 = + [ 2² + 1/4+25 1 ² + √√ 16+7 7² + | √²+25)² +16 + - √√16+97² +1 √4²7251²] ]. ₂/52+1 51 = £[9+49 +25+ 26 +16+ 26+ 25 +41 = x 209 f 1226.125
(C) x (K) = x* (-k) ₂ x * (N-K) 2 428, x * (11 = ** (-7) X (1) 2 x * (-7) x (1) ² 4 + 5 j × (-7)=4-5j x (2) ² - 4-3) = x² (6) = −4+3j x(3) = x * (3) 1-51° = Hence given signal is even signal. роя even x* (8-7)=
thanks
The work below was done by the other people but I'm pretty sure
that there is something odd with the answer (you could also start
with this but please state what's wrong with it)
If the DFT of x[n] with period N = 8 is X[k] = {3,4 + 5j, −4 − 3j, 1 + 5j, −4, 1 − 5j, −4+ 3j,4 − 5j}. (a) Find the average value of x[n] (b) Find the signal power of x[n]. (c) Is x[n] even or odd or neither.
given зат OFT of xmn, N28 x(²) 2 √ 3, 4 +55.-4-35, 1+55, -4,1-55, -4+85, 4-55 4 са, Average value испра 3+4+5j-4-3j +1+5j-4+-s] -4+3j+4-sj g ItJo 8 (11= 0.125
(6) signal power p² = { 1 [~ 111] 1² 2= N 3 2 2 = = [2 (0)² + [51] ² + [5 (²1)² + ((31) ²³ + (5 (41)² + (a(sy) ² + [~ [6₁] ² + [~ (+1]²] 2 2 = & [ 3² + |( 4 +5√ √ √(- 4 - 3 5 ) 1³² + |(1 + 5√² ) ² + (-4/²) + | 11-5; }} +1 (4 + 3√11² +K4-sjj1|² ] 2 3 = + [ 2² + 1/4+25 1 ² + √√ 16+7 7² + | √²+25)² +16 + - √√16+97² +1 √4²7251²] ]. ₂/52+1 51 = £[9+49 +25+ 26 +16+ 26+ 25 +41 = x 209 f 1226.125
(C) x (K) = x* (-k) ₂ x * (N-K) 2 428, x * (11 = ** (-7) X (1) 2 x * (-7) x (1) ² 4 + 5 j × (-7)=4-5j x (2) ² - 4-3) = x² (6) = −4+3j x(3) = x * (3) 1-51° = Hence given signal is even signal. роя even x* (8-7)=