Answer Happy

Using lambdas and recursive functions (no loops) write a
procedure in Racket that returns the n-th line of Pascal's triangle
as a list.
At this point, I haven't even begun to add the lambdas. I'm
just trying to get the function to work. My ultimate goal is to
make a function that accepts the "n" value and returns that single
row of Pascal's triangle in the form of a list. Right now I'm
trying to get a function to accept two variables, a list, and a
number (row).
The way I was planning on solving this challenge was by taking
the second, (1 1), row of pascals triangle, adding a zero to the
list, reversing the list, then adding the two values to get the
next row. i.e. (0 1 1) + (1 1 0) gives (1 2 1), (1 2 1 0) + (0 1 2
1) = (1 3 3 1)... nth number.
Now I know that the second number in the returned list will
equal the nth number if done correctly. I wanted to test that in
the function to tell it to stop the recursion. However, I don't
think I've done that correctly. Please help!
#lang racket
; Using lambdas and recursive functions (no loops)
; write a procedure in Racket that returns the n-th
; line of Pascal's triangle as a list.
(define listn
(list 0 1 1))
(define (added-lists listn rowNum)
(define tmpList
(reverse listn))
(define newList
(map + listn tmpList))
(if (= rowNum 0)
'(1)
(if (= rowNum 1)
'(1 1)
(if (= (second newList) rowNum)
newList
(added-lists newList rowNum)))))
(define (pascals n)
(added-lists listn n))