Question 11 200 mm 2 pts 200 mm 200 mm 200 mm Two L-shaped arms each of mass 5 kg are welded at the one-third points of
Posted: Thu May 05, 2022 12:34 pm
Question 11 200 mm 2 pts 200 mm 200 mm 200 mm Two L-shaped arms each of mass 5 kg are welded at the one-third points of the 600 mm shaft
200 mm Two L-shaped arms, each of mass 5 kg, are welded at the one-third points of the 600 mm shaft AB to form the assembly shown. Originally the assembly rotates at the constant rate of 360 rpm. Part of the solution on how to determine the angular momentum HA of the assembly about point A is shown below. Use the values below to determine the magnitude of the angular momentum HA of the assembly about point A in kg.m²/s, using the NEWw=388 rpm. Round your answer to One decimal place. Hint: Calculate (Ho)x. (Holy and (Ho)z then find the magnitude of HA HG in this case. Use the summation of the moments of inertia given at the bottom of the table. = m = 5 kg. a = 200 mm = 0.2 m (27)(360) @= = 127 rad/s. 00₂ = 0, 0,= 0, 0 = 127 rad/s 60
N B RIP Of the assembly about point A is shown below. Use the values below to determine the magnitude of the angular momentum HA of the assembly about point A in kg.m³/s, using the NEWw=388 rpm. Round your answer to One decimal place. Hint: Calculate (Holx. (Holy and (Ha)z then find the magnitude of HA HG in this case. Use the summation of the moments of inertia given at the bottom of the table. m = 5 kg. a 200 mm 0.2 m (2)(360) 60 =127 rad/s @, - 0, @o, = 0, 00=12r rad's Use parallel axes x, y, with origin at the mass center as shown. 4 a (Ha), = -1, a (HG), = -1,00 (Ha), = To Segments 1, 2, 3, and 4, each of mass m² = 2.5 kg, contribute to TT and T. ya lyz a Part Ja a %² a 19 1x 4
2 Part 3 4 le m'a² m'a² 9 Segments 1, 2, 3, and 4, each of mass - 2.5 kg. contribute to T... 7,, and 7, 1₂ 0 0 -m'a² -14 1|2 m'a² (1/2+1/+1) ³²² 10
200 mm Two L-shaped arms, each of mass 5 kg, are welded at the one-third points of the 600 mm shaft AB to form the assembly shown. Originally the assembly rotates at the constant rate of 360 rpm. Part of the solution on how to determine the angular momentum HA of the assembly about point A is shown below. Use the values below to determine the magnitude of the angular momentum HA of the assembly about point A in kg.m²/s, using the NEWw=388 rpm. Round your answer to One decimal place. Hint: Calculate (Ho)x. (Holy and (Ho)z then find the magnitude of HA HG in this case. Use the summation of the moments of inertia given at the bottom of the table. = m = 5 kg. a = 200 mm = 0.2 m (27)(360) @= = 127 rad/s. 00₂ = 0, 0,= 0, 0 = 127 rad/s 60
N B RIP Of the assembly about point A is shown below. Use the values below to determine the magnitude of the angular momentum HA of the assembly about point A in kg.m³/s, using the NEWw=388 rpm. Round your answer to One decimal place. Hint: Calculate (Holx. (Holy and (Ha)z then find the magnitude of HA HG in this case. Use the summation of the moments of inertia given at the bottom of the table. m = 5 kg. a 200 mm 0.2 m (2)(360) 60 =127 rad/s @, - 0, @o, = 0, 00=12r rad's Use parallel axes x, y, with origin at the mass center as shown. 4 a (Ha), = -1, a (HG), = -1,00 (Ha), = To Segments 1, 2, 3, and 4, each of mass m² = 2.5 kg, contribute to TT and T. ya lyz a Part Ja a %² a 19 1x 4
2 Part 3 4 le m'a² m'a² 9 Segments 1, 2, 3, and 4, each of mass - 2.5 kg. contribute to T... 7,, and 7, 1₂ 0 0 -m'a² -14 1|2 m'a² (1/2+1/+1) ³²² 10