Only answer the bolded portion (3). ***The non bolded is for reference only***
Posted: Thu May 05, 2022 12:32 pm
Only answer the bolded portion (3).
***The non bolded is for reference only***
2) Referring to Appendix " A 3" of your text and beam figure 7th from the top and 2nd from the bottom, a Fixed-ended beam with Concentrated load "P" at midspan. a) P=Pu=97.33 kips and L-18 ft. Using Fy-50 ksi steel, design a W18 section and specify its unbraced length Lp. b) Draw a figure of the beam and specify the placement of the horizontal braces using an "X" on the compression flanges. 3) For the beam of problem 2. and the selected W18 section, a) Using the section properties "Z" to calculate Phi Mp, and compare to the Mu, max, from the beam b) Use the appropriate equation in the text to calculate the unbraced length Lp of the selected W-section c) Use the appropriate section properties to calculate the deflection under the Load Pn.
APPENDIX A.3 Shears, Moments, and Deflections Loading 14* R R4 R₁ T Lx R R₁ K 2 a 2 wl ➜ 2 2 a R₂ R +R Shear Force Diagram x Shear V▬▬▬▬ Shear V [1, Shear Shear Mmax Mmax Mmas ↓ Mmax Moment Diagram Moment Moment Moment. Moment Maximum Moment Pl 4 Pab 1 at x = a Pa wl2 8 Slope at End PI² 16EI Pa(l²-a²) 6EI at R₂ Pa(l-a) 2EI w/³ 24EI Maximum Deflection Pl³ 48 EI Pb(1²-b²)3/2 9√3 Ell at x = 11²-6² 3 Pa(31²-4a²) 24EI 5 wl 384 EI (Continued)
APPENDIX A.3 (Continued) Shears, Moments, and Deflections Loading W R₁4 R₂ R a b R V₂ Shear Force Diagram III 0.5774/ Shear Shear Shear Shear Mmax Y Mmax Moment Diagram 0.5774/ Moment Moment Moment Moment M Mm Maximum Moment w/² 9√3 w/² 12 -Pl -Pb Slope at End 8w1³ 360EI at R₂ 5wl³ 192EI PL² 2EI Pb² 2EI Maximum Deflection 2.5w/4 384 EI at x = 0.519/ wl 120EI P1³ 3EI Pb² (31-b) 6EI at free end (Continued)
APPENDIX A.3 (Continued) Shears, Moments, and Deflections Loading wl R tw R R wl R R + 1/20 Note: w, load per unit length; W, total load. Shear Shear Shear Force Diagram Shear Shear Moment Moment Mmax M₁ Moment Diagram A Max Moment 0.211/ + Moment Mmax Mmax Mmax ↑ Maximum Moment w/² 2 w/² 6 PL 8 w/² 12 Slope at End w/³ 6EI w/³ 24 EI 0 0 Maximum Deflection wla SEI wlª SEI P1³ 192EI wl 384EI
***The non bolded is for reference only***
- Only Answer The Bolded Portion 3 The Non Bolded Is For Reference Only 1 (89.72 KiB) Viewed 22 times
- Only Answer The Bolded Portion 3 The Non Bolded Is For Reference Only 2 (72.78 KiB) Viewed 22 times
APPENDIX A.3 Shears, Moments, and Deflections Loading 14* R R4 R₁ T Lx R R₁ K 2 a 2 wl ➜ 2 2 a R₂ R +R Shear Force Diagram x Shear V▬▬▬▬ Shear V [1, Shear Shear Mmax Mmax Mmas ↓ Mmax Moment Diagram Moment Moment Moment. Moment Maximum Moment Pl 4 Pab 1 at x = a Pa wl2 8 Slope at End PI² 16EI Pa(l²-a²) 6EI at R₂ Pa(l-a) 2EI w/³ 24EI Maximum Deflection Pl³ 48 EI Pb(1²-b²)3/2 9√3 Ell at x = 11²-6² 3 Pa(31²-4a²) 24EI 5 wl 384 EI (Continued)
APPENDIX A.3 (Continued) Shears, Moments, and Deflections Loading W R₁4 R₂ R a b R V₂ Shear Force Diagram III 0.5774/ Shear Shear Shear Shear Mmax Y Mmax Moment Diagram 0.5774/ Moment Moment Moment Moment M Mm Maximum Moment w/² 9√3 w/² 12 -Pl -Pb Slope at End 8w1³ 360EI at R₂ 5wl³ 192EI PL² 2EI Pb² 2EI Maximum Deflection 2.5w/4 384 EI at x = 0.519/ wl 120EI P1³ 3EI Pb² (31-b) 6EI at free end (Continued)
APPENDIX A.3 (Continued) Shears, Moments, and Deflections Loading wl R tw R R wl R R + 1/20 Note: w, load per unit length; W, total load. Shear Shear Shear Force Diagram Shear Shear Moment Moment Mmax M₁ Moment Diagram A Max Moment 0.211/ + Moment Mmax Mmax Mmax ↑ Maximum Moment w/² 2 w/² 6 PL 8 w/² 12 Slope at End w/³ 6EI w/³ 24 EI 0 0 Maximum Deflection wla SEI wlª SEI P1³ 192EI wl 384EI