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Posted: **Thu May 05, 2022 12:10 pm**

: For The Beam Shown Below Draw The Reactions In The Positive Coordinate Directions And Calculate W Lb Ft A Ax L Ft W 1 (46.21 KiB) Viewed 23 times

: For The Beam Shown Below Draw The Reactions In The Positive Coordinate Directions And Calculate W Lb Ft A Ax L Ft W 2 (26.64 KiB) Viewed 23 times

: For The Beam Shown Below Draw The Reactions In The Positive Coordinate Directions And Calculate W Lb Ft A Ax L Ft W 3 (10.9 KiB) Viewed 23 times

For the beam shown below, draw the reactions in the positive coordinate directions and calculate: w lb/ft A Ax L ft w = 80 lb/ft P = 70 lb L = 8 ft a = 5 ft b = 3 ft 0= 70 deg COLLAPSE IMAGES a ft Plb X. 0 b ft B By
The horizontal reaction at A. 3 tries remaining. 1 point(s) possible The vertical reaction at A. 3 tries remaining. 1 point(s) possible The vertical reaction at B. 3 tries remaining. 1 point(s) possible The range for section 1. ( < X< 3 tries remaining. 1 point(s) possible The shear force equation for section 1. lb 3 tries remaining. 1 point(s) possible lb lb lb ) ft ENTER ENTER ENTER ENTER ENTER
The bending moment equation for section 1. lb.ft ENTER 3 tries remaining. 1 point(s) possible The range for section 2. ( < X< ENTER 3 tries remaining. 1 point(s) possible The shear force equation for section 2. lb ENTER 3 tries remaining. 1 point(s) possible The bending moment equation for section 2. lb.ft ENTER 3 tries remaining. 1 point(s) possible The range for section 3. ( < X< ) ft ENTER 3 tries remaining. 1 point(s) possible ) ft
The shear force equation for section 3. lb ENTER 3 tries remaining. 1 point(s) possible The bending moment equation for section 3. lb.ft ENTER 3 tries remaining. 1 point(s) possible