Using Moment Distribution Method: 1. Solve the moment and support reaction of all the girder: G2,G9, G10, G7 and G6 2. S
Posted: Thu May 05, 2022 11:51 am
Using Moment Distribution Method:
1. Solve the moment and support reaction of all the girder:
G2,G9, G10, G7 and G6
2. Solve for the moment and support reaction of all beams: B2,
B7, B4, B6
Other Information:
1. Use service load of 35.9328 kN/m for the third floor and
19.6528 kN/m in second floor
2. For beams b = 200 mm and h = 350 mm
3. For girders b = 300 mm and h = 450 mm
4. For column use 300 by 300 mm
5. For column use 300 by 300 mm
Third Floor:
Second Floor:
Detailed Drawing:
G7 G10 2050 $3 82 G1 S1 B4 $1 G4 St B6 CS 1950 $1 G6 $1 B6 (E) 69 G10
G7 G10 2050 $3 82 G1 S1 B4 $1 G4 St B6 CS 1950 $1 G6 $1 B6 (E) 69 G10
G₂ 2.05 A D G I L O Q S 2wm B2 B7 B2 1.as Всі J G4 m В6 GG е B6 2.0m F $1+ k N P MO 2.0m 1.575m 1.575m 2.30m R + 2.53m 1.0m Ga Gq Gio
1. Solve the moment and support reaction of all the girder:
G2,G9, G10, G7 and G6
2. Solve for the moment and support reaction of all beams: B2,
B7, B4, B6
Other Information:
1. Use service load of 35.9328 kN/m for the third floor and
19.6528 kN/m in second floor
2. For beams b = 200 mm and h = 350 mm
3. For girders b = 300 mm and h = 450 mm
4. For column use 300 by 300 mm
5. For column use 300 by 300 mm
Third Floor:
Second Floor:
Detailed Drawing:
G7 G10 2050 $3 82 G1 S1 B4 $1 G4 St B6 CS 1950 $1 G6 $1 B6 (E) 69 G10
G7 G10 2050 $3 82 G1 S1 B4 $1 G4 St B6 CS 1950 $1 G6 $1 B6 (E) 69 G10
G₂ 2.05 A D G I L O Q S 2wm B2 B7 B2 1.as Всі J G4 m В6 GG е B6 2.0m F $1+ k N P MO 2.0m 1.575m 1.575m 2.30m R + 2.53m 1.0m Ga Gq Gio