How many grams of Al₂O3 can form from 35.9 g of Al? 4 Al(s) + 30₂(g) → -2 Al₂O3(s) Step 1: Show the strategy for solving
Posted: Wed May 04, 2022 4:02 pm
How many grams of Al₂O3 can form from 35.9 g of Al? 4 Al(s) + 30₂(g) → -2 Al₂O3(s) Step 1: Show the strategy for solving this problem. grams Al→→→→→ Answer Bank grams A1,0₂ moles Al grams Al grams 0, moles Al₂O3 moles O Step 2: Show the conversions required to solve this problem and calculate the grams of Al₂O3. 35.9 g Al x = g Al₂O3 Answer Bank grams of Al₂O3: 26.98 g Al 1 mole 0, 1 mole Al 1 mole Al₂O3 3 moles O, 4 moles Al grams Al₂O3 32.00 g 0₂ 101.96 g Al₂O3 2 moles Al₂O3 g Al₂O3