Answer Happy

I need to know from where the 2.9x 10^-7 came.
Salts of Strong Bases and Weak Acids The cyanide ion, CN, the anion of hydrocyanic acid, HCN. For HCN, K, -4.0 x 10-10. CN + H₂OHCN + OH [HCN] [OH] [CN] K K₂ K₁ for HCN 1.0×10-¹4 K₂ -=2.5x10-5 4.0x10-10 Salts of Strong Bases and Weak Acids Set up the equation for the hydrolysis and the algebraic representations of the equilibrium concentrations. CIO HCIO + OH- Initial: 0.10M OM ОМ Change: -xM +xM + xM At equil: (0.10-x) M xM xM Salts of Strong Bases and Weak Acids Example 2: Calculate [OH-]. pH and percent hydrolysis for the hypochlorite ion in 0.10 M sodium hypochlorite, NaCIO, solution. "Clorox", "Purex", etc., are 5% sodium hypochlorite solutions. -100% in H₂O Na* + C10 NaCIO (0) 0.10M 0.10M 0.10M Salts of Strong Bases and Weak Acids - Substitute the algebraic expressions into the hydrolysis constant expression. K₂ [HCIO][OH]_2.9×10-7 [CIO] (x)(x) K₂ = 2.9×10-² (0.10-x) =