When [Pb²+] = 1.33 M, the observed cell potential at 298 K for an electrochemical cell with the reaction shown below is
Posted: Wed May 04, 2022 3:15 pm
When [Pb2+]
= 1.33 M, the observed cell potential at
298 K for an electrochemical cell with the reaction shown below
is 0.684 V. What is
the Cr3+ concentration in
this cell?
3Pb2+(aq) + 2Cr(s) 3Pb(s) + 2Cr3+(aq)
[Cr3+] = mol/L
i need answer now thank you!!
When [Pb²+] = 1.33 M, the observed cell potential at 298 K for an electrochemical cell with the reaction shown below is 0.684 V. What is the Cr³+ concentration in this cell? 3Pb²+ (aq) + 2Cr(s) 3Pb(s) + 2Cr³+ (aq) [Cr³+] = mol/L
= 1.33 M, the observed cell potential at
298 K for an electrochemical cell with the reaction shown below
is 0.684 V. What is
the Cr3+ concentration in
this cell?
3Pb2+(aq) + 2Cr(s) 3Pb(s) + 2Cr3+(aq)
[Cr3+] = mol/L
i need answer now thank you!!
When [Pb²+] = 1.33 M, the observed cell potential at 298 K for an electrochemical cell with the reaction shown below is 0.684 V. What is the Cr³+ concentration in this cell? 3Pb²+ (aq) + 2Cr(s) 3Pb(s) + 2Cr³+ (aq) [Cr³+] = mol/L