Answer Happy

Consider a steadily accelerating motion in the X-direction in Minkowski's space. In this case, the speed and acceleration apply dt dx¹ U⁰_ U¹ duº du¹ A¹ =C = Aº- and U- U=c², A. U=0, A• A=-g² 2 dr dr dr dr d²u⁰ d²u¹ 2 We know that g -U1 dz² dr² c² initial condition => Derive the solutions of the equations with the initial condition U¹ (0)=0, Uº (0)=c, A¹ (0)=g, A°(0)=0. The result is convenient to pronounce the form |U¹= 1 dx gt gt == -=csinh| dt U=c=ccosh dt dt C C With the results, initial condition x(r=0)=- -, t(T-0)=0 show that the place and time coordinates x and t g implement c c²₁²_x²=C² g من