P₁ = P₁+pg h₁ p = m/V F₁/A₁=F₂/A₂ P₁A₁V₁ = P2A₂V2 A₁V₁= A₂V₂ P + pv₁² +pgy = constant P₁ + ½ pv₂² +p gy₁ = P₂ + ½ pv₁2 +
Posted: Wed May 04, 2022 1:17 pm
- P P Pg H P M V F A F A P A V P2a V2 A V A V P Pv Pgy Constant P Pv P Gy P Pv 2 1 (15.73 KiB) Viewed 39 times
- P P Pg H P M V F A F A P A V P2a V2 A V A V P Pv Pgy Constant P Pv P Gy P Pv 2 2 (29.44 KiB) Viewed 39 times
- P P Pg H P M V F A F A P A V P2a V2 A V A V P Pv Pgy Constant P Pv P Gy P Pv 2 3 (32.9 KiB) Viewed 39 times
1) Calculate the weight of the water filling an aquarium measuring 3 m X 1 m X 0.5 m if the density of water is 1.00 X 10³ kg/m³? 2) A partially filled oil tank contains very heavy oil having a density of 9.00 g/ cm³ and a height of 5 m. Due to a valve failure light crude oil having a density of 0.500 g/ cm³ has flooded the tank to a depth of 4m. Find the pressure at the bottom of the oil tank shown below in cross section if the weight of air is 1.013 x 10³ Pa.? Air Light Oil Am Heavy Oil 5m 3) In a car lift at a service station, compressed air exerts a force on a small piston of circular cross sectional radius of 3 cm. The pressure is transmitted to an incompressible liquid to a second piston having a radius of 10 cm. What force must the compressed air exert on the small piston in order to lift a car weighting 15,000 N? (Area piston = m²)
-1) 19,700M 2) 167,400 Pa 3) 1350 N