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The accompanying table shows the market share for automotive manufacturers in 2013. Also shown is the frequency of car purchases by manufacturer from a random sample of 210 customers in March of 2018. Use these data to complete parts a and b. Manufacturer Market Share 2013 (%) Frequency 2018 D A 37 19.2% 17.3% B 31 C 14.2% 28 D 11.4% 28 E 11.1% 17 Other 26.8% 69 Total 100% 210 a. Using a = 0.05, perform a chi-square test to determine if the market share in the automotive industry has changed between 2013 and 2018. What is the null hypothesis, Ho?
What is the null hypothesis, Ho? O A. The distribution of manufacturer's market shares differs from the claimed or expected distribution. O B. The distribution of manufacturer's market shares is 19.2% manufacturer A, 17.3% manufacturer B, 14.2% manufacturer C, 11.4% manufacturer D, 11.1% manufacturer E, and 26.8% from other manufacturers. OC. The distribution of manufacturer's market shares follows the normal distribution. O D. The distribution of manufacturer's market shares is 37 manufacturer A, 31 manufacturer B, 28 manufacturer C, 28 manufacturer D, 17 manufacturer E, and 69 from other manufacturers. What is the alternative hypothesis, H₁ ? OA. The distribution of manufacturer's market shares is the same as the claimed or expected distribution. O B. The distribution of manufacturer's market shares differs from the claimed or expected distribution. O C. The distribution of manufacturer's market shares is 20% manufacturer A, 20% manufacturer B, 20% manufacturer C, 20% manufacturer D, and 20% from other manufacturers. O D. The distribution of manufacturer's market shares does not follow the normal distribution.
The test statistic is (Round to two decimal places as needed.) b. Determine the p-value for the chi-square test statistic using Excel and interpret its meaning. Identify a function that can be used in Excel to directly calculate the p-value (with no other calculations needed other than calculating the arguments of the function itself). Determine the p-value. p-value = (Round to three decimal places as needed.) Interpret the p-value. The p-value is the probability of observing a value for the test statistic the calculated test statistic, assuming
Interpret the p-value. The p-value is the probability of observing a value for the test statistic Draw a conclusion. Because the p-value is ▼α = 0.05, the calculated test statistic, assuming Ho. At the 5% significance level, there enough evidence to conclude that the distribution of education levels the