Answer Happy • 4. S 5. f 6. dxxx¹/5x(lnx) (x+1)(x+3) dzxe¹/= (z+1)(z²+1)(z²+9)(z+3) de 3/2+cos (0) ; 7. 1.th on the circle |z| = 2 daxe

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4. S 5. f 6. dxxx¹/5x(lnx) (x+1)(x+3) dzxe¹/= (z+1)(z²+1)(z²+9)(z+3) de 3/2+cos (0) ; 7. 1.th on the circle |z| = 2 daxe

Posted: Wed May 04, 2022 11:08 am

by answerhappygod

: 4 S 5 F 6 Dxxx 5x Lnx X 1 X 3 Dzxe Z 1 Z 1 Z 9 Z 3 De 3 2 Cos 0 7 1 Th On The Circle Z 2 Daxe 1 (23.16 KiB) Viewed 36 times

4. S 5. f 6. dxxx¹/5x(lnx) (x+1)(x+3) dzxe¹/= (z+1)(z²+1)(z²+9)(z+3) de 3/2+cos (0) ; 7. 1.th on the circle |z| = 2 daxeikz 1+² with k>0 [4