Answer Happy

Consider the 10 X 106 m³ lake analyzed in Example 5 which, under the conditions given, was found to have a steady-state pollution concentration of 3.5 mg/L (time, t < 0). The pollution is non-conservative with reaction rate constant kd =0.20/day. At t=0, Cw was immediately shifted from 100.0 mg/L to to 0 mg/L, and then kept at 0 mg/L until 3 day, and finally shifted up to 50.0 mg/L Regardless of the Cw values, the outgoing flow Qw is always 0.5 m³/s. Assuming complete mix conditions, find the concentration of pollutant in the lake (C) as a function of time (t) when t > 0, and draw its corresponding plot of the pollutant concentration (C) versus time (t) (i.e., X-axis variable is t, and Y-axis variable is C) t < 0 day steady state 0 ≤ t < 3 day 3 day st Outfall Outfall Q=0.5 m³/s Cu = 10.0 mg/Li Qu=0.5 m³/s C. = 100.0 mg/L Outfall Qv=0.5 m³/s Cw= Lake Lake Incoming stream Incoming stream Incoming stream V=10.0 x 10 m²³ k=0.20/day V= 10.0x 10 m³ k=0.20/day Q₁=5.0 m³/s Q₁=5.0 m³/s Q₁=5.0 m²/s C. =100 mg/L -C= 3.5mg/L -C=? C =100 mg/L C = 10.0 mg/L. regat diper Figa 01-07 Figa 01-07 Copyright©2008 Porson Price Hall,Inc Copyright ©2000 Pearson Prentice Hall,Inc Outgoing Cm=? Qm=? Outgoing Cm=? Qm=? 50.0 mg/L Lake N V 10.0 x 10 m k=0.20/day -C=? Figure: 01.07 Copyright©2006 Pearson Prentice Hall, Inc. Outgoing Cm=? Q=?