NEED HELP ASAP. PLEASE SHOW THE DETAILED SOLUTION ON THE BOXED PART. SHOW THE INTEGRATION SOLUTION.THANK YOU.
Posted: Wed May 04, 2022 8:36 am
NEED HELP ASAP. PLEASE SHOW THE DETAILED SOLUTION ON THE BOXED
PART. SHOW THE INTEGRATION SOLUTION.THANK YOU.
W.S (t = 0) 13. In Fig. H is shown a tank 1.5 by 1.5m horizontal section and 3m high with two orifices (C=0.60) both 10cm in diameter and 60cm apart. (a) How much water must be supplied to the tank to keep it always full? (b) If this supply is cut off, how long Given: AT = 2.25m; hr = 3m 1.5 m by 1.5 m Dot 10 cm or 0.10m Do2 = 10 cm or 0.10m C=0.60 Find: QT =? t=? 1.20 m 0.60 m orifice (1) crifice (2) 100
Solution: a.) Q = CA,√2gh Q₁ = (0.6) (π) (0.005)2/19.62(1.2) = 0.0229 m3/s Q2 = (0.6) (7) (0.05)2/19.62(1.8) Q2 = 0.028 m3/s QT Q₁ + Q2 = 0.0229 + 0.028 QT = 0.051 m3/s h1 Adh b.)t₁ = ² CA√ √2gh-Q 1.2 2.25dh (2) (0.6) (n)(0.05)^2√19.6h-0.051 900 = 118.0817- 17 t₁= 65.1405 s 1.8 2.25dh t₂ = (2)(0.6) (π) (0.05)^2√19.6h-0.051 900 = 61.1236- 17 t₂ = 8.1824 s T = t₁ + t₂ T = 65.1405 +8.1824 T = 73.32 s
PART. SHOW THE INTEGRATION SOLUTION.THANK YOU.
- Need Help Asap Please Show The Detailed Solution On The Boxed Part Show The Integration Solution Thank You 1 (44.01 KiB) Viewed 21 times
Solution: a.) Q = CA,√2gh Q₁ = (0.6) (π) (0.005)2/19.62(1.2) = 0.0229 m3/s Q2 = (0.6) (7) (0.05)2/19.62(1.8) Q2 = 0.028 m3/s QT Q₁ + Q2 = 0.0229 + 0.028 QT = 0.051 m3/s h1 Adh b.)t₁ = ² CA√ √2gh-Q 1.2 2.25dh (2) (0.6) (n)(0.05)^2√19.6h-0.051 900 = 118.0817- 17 t₁= 65.1405 s 1.8 2.25dh t₂ = (2)(0.6) (π) (0.05)^2√19.6h-0.051 900 = 61.1236- 17 t₂ = 8.1824 s T = t₁ + t₂ T = 65.1405 +8.1824 T = 73.32 s