Lolton = 0 Y 500 hiha * =P = f = Mn = Max ? zby Y) *=w 2) Ph way X = c has in. 2 gy PE N 250 JE AN N. woboN ty for Tra
Posted: Tue May 03, 2022 6:39 am
- Lolton 0 Y 500 Hiha P F Mn Max Zby Y W 2 Ph Way X C Has In 2 Gy Pe N 250 Je An N Wobon Ty For Tra 1 (18.01 KiB) Viewed 40 times
- Lolton 0 Y 500 Hiha P F Mn Max Zby Y W 2 Ph Way X C Has In 2 Gy Pe N 250 Je An N Wobon Ty For Tra 2 (18.01 KiB) Viewed 40 times
- Lolton 0 Y 500 Hiha P F Mn Max Zby Y W 2 Ph Way X C Has In 2 Gy Pe N 250 Je An N Wobon Ty For Tra 3 (50.57 KiB) Viewed 40 times
- Lolton 0 Y 500 Hiha P F Mn Max Zby Y W 2 Ph Way X C Has In 2 Gy Pe N 250 Je An N Wobon Ty For Tra 4 (25.06 KiB) Viewed 40 times
PE N 250 JE AN N. woboN ty for Translation Equilibrium INGENO 3 Nocotyf for static friction on 30 cott & kg Ny 4 де и w 30 Cofy S us 60 1 20 60 NSN Remember The Theorem which tells that if not force body w 1420. torque to any beint in Fry Rotsional equilibrium that so about any print We take Butuhande bulut Rotational Equilibmum Gon of sthy - NJ Sint cours easy NL Siny #30 cos4 = Ni Siny > Ni= 30-ty 0.839 2 ug 0.42
L zom, w=50N, 450, N=2 fs = P, now Pin - Wit V. I cox 4 Р W 들 P- N 200977 w 2 tany 50 2 tansol 2 NOWY fs EP = Psy = atany Us 3 / 2 10.4195 atany 2 tanso