Answer Happy

A car of mass 1000kg is at the top of a 10 degree hill as shown. What is its gravitational potential energy relative to the bottom of the hill? 10- 50 m . O U - 1000kg 9.8m/s 2 x 50m X sin(10) - 8.5 x 104, U - 1000kg X 9.8m/s 2 x 50m X tan(10) - 8.6 x104 O U = 1000kg x 50m - 5.0 X 105 O U = 1000kg x 9.8ms 2 x 50m - 4.9 X 105 U - 1000kg X 9.8m/s 2 x 50m X 10 - 4.9 X 109 QUESTION 9
QUESTION 9 if the car rolls down the hill (with the engine off) with negligible friction and air resistance, what wil its kinetic energy be when it reaches the bottom of the han Note about format if using scientific notation. This system uses E in place of xt0 sa for example to enter 3x10-24 type 36-24 in the answer box QUESTION 10 Suppose instead that the amount of work done on the car by the frictional and resistance forces as the car rolls down the hills 49.999. What then is the kinetic energy of the car when it reaches the bottom of the Note about formatsing dentific notation. This system uses in place of x10 so for example to enter 3x10-24 type 24 in the answer box