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1563 - 153.85 127.30 29 IS ET SE TOT 1025 300 SOEL Acer 20.45 AC 13C NMR 4-Methylembelliferone (CD(C=O)CD3, 101 MHz) ste

Posted: Mon May 02, 2022 6:04 pm
by answerhappygod
1563 153 85 127 30 29 Is Et Se Tot 1025 300 Soel Acer 20 45 Ac 13c Nmr 4 Methylembelliferone Cd C O Cd3 101 Mhz Ste 1
1563 153 85 127 30 29 Is Et Se Tot 1025 300 Soel Acer 20 45 Ac 13c Nmr 4 Methylembelliferone Cd C O Cd3 101 Mhz Ste 1 (32.09 KiB) Viewed 41 times
1563 153 85 127 30 29 Is Et Se Tot 1025 300 Soel Acer 20 45 Ac 13c Nmr 4 Methylembelliferone Cd C O Cd3 101 Mhz Ste 2
1563 153 85 127 30 29 Is Et Se Tot 1025 300 Soel Acer 20 45 Ac 13c Nmr 4 Methylembelliferone Cd C O Cd3 101 Mhz Ste 2 (21.77 KiB) Viewed 41 times
1563 - 153.85 127.30 29 IS ET SE TOT 1025 300 SOEL Acer 20.45 AC 13C NMR 4-Methylembelliferone (CD(C=O)CD3, 101 MHz) ste *C NMR (101 MHz, Acetone) & 161.89, 161.06, 156.38, 153.85, 127.30, 113.67. 113.51, 111.84, 103.35, 30.45, 18.54. A 20026 11184 HI 111 $1 -
How many unique carbon signals are expected for compound (1)? Are the appropriate number of peaks present? (you may need to expand the spectrum) Which hydrogen(s) would be assigned to 18.5 ppm? The carbon signal of an ester C-O is estimated to be 1600-1800 ppm. Explain why compound (1)'s carbonyl is on the lower end of this range around 161 ppm. 3