14 (1₁6) = √2π Jak p(K)e! nd - dk SUTTO (za ju ikx - (1/4 at in
Posted: Mon May 02, 2022 5:20 pm
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how this integration is performed???
14 (1₁6) = √2π Jak p(K)e! nd - dk SUTTO (za ju ikx - (1/4 at in</2m) k² 1/4 C гупа (뜸) (24) "* Juma JT ( Fat the )J" Cuffox ( +2 (1+ 2ihat J^/^ exp [-x² ( ² = + 2i^²) (zaj 14. (1+ 2 m 2014 2iht m in ) )
- 1 (319.86 KiB) Viewed 24 times
14 (1₁6) = √2π Jak p(K)e! nd - dk SUTTO (za ju ikx - (1/4 at in</2m) k² 1/4 C гупа (뜸) (24) "* Juma JT ( Fat the )J" Cuffox ( +2 (1+ 2ihat J^/^ exp [-x² ( ² = + 2i^²) (zaj 14. (1+ 2 m 2014 2iht m in ) )