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The surface of a hollow conducting sphere of inner radius Ris divided into two equal hemispheres by a plane. The plane i
Posted: Mon May 02, 2022 4:59 pm
by answerhappygod
- The Surface Of A Hollow Conducting Sphere Of Inner Radius Ris Divided Into Two Equal Hemispheres By A Plane The Plane I 1 (29.07 KiB) Viewed 33 times
The surface of a hollow conducting sphere of inner radius Ris divided into two equal hemispheres by a plane. The plane intersects with z axis as shown below (x axis is out of the page). The segments are kept at v()=+V for 0 SØST V®)=-V for a<$<2n Determine the potential inside the sphere for up to 1=1 term (includingl =1) and verify that it is given by 0(1,0.6)=xxiv, sinósing... Do not rotate the axis and use spherical coordinate. You will need to use Spherical harmonics to solve this. -V + V