I need the answer for this question.
Posted: Mon May 02, 2022 4:58 pm
I need the answer for this question.
This is Discard and increase equation: Construct a circle 8 cm in diameter, trace an optical axis (the one that passes through the middle of the circle) and indicate the center of curvature C (it is the same center of the circle), the focal point f (it is half the distance from vertex to center of curvature C). A) draw a little arrow located further from the center of curvature C, away from the focus f and away from the vertex in the concave part Trace the rays and obtain the image and draw it this will be point i (distance between the vertex and the image) Verify that the value of i (where the image is) by measuring directly with a ruler from the vertex to the point i, and compare it using the Descartes equation 1/f = 1/i+1/0 where i is the position or distance of the image measured from the vertex and that in this problem is the unknown to find. or, is the position of the object measured from the vertex and f is the position or distance of the focus measured from the vertex. Determine the magnification A using A = -1/0, and compare it to what the little arrow of the obtained image measures directly, (remember that the negative values indicate that the image is inverted) B. Make another circle 8 cm in diameter and now place or graph the arrow (the object) between C and F, that is, between the center of curvature and the focus. Calculate the position of the image directly with a ruler, as well as calculate it using Descartes' equation to compare if the results give the same or approximate. Also proceed to find and compare the values of the increase as in part A. C. Make another circle of 8 cm in diameter and locate the object, that is, the arrow between the focus and the vertex and find the image again, calculate with the rule how far the image is from the vertex, this is the value of i, then compare it with Descartes's equation 1/f = 1/i +1 / 0 to find the value of i again. Finally, calculate directly whether the image of the arrow increases or not, directly measure the size of the arrow with the ruler and compare it by obtaining it from the formula A = -1 /0, where i is the distance from the vertical to the image, i is the distance from vertex to object.
This is Discard and increase equation: Construct a circle 8 cm in diameter, trace an optical axis (the one that passes through the middle of the circle) and indicate the center of curvature C (it is the same center of the circle), the focal point f (it is half the distance from vertex to center of curvature C). A) draw a little arrow located further from the center of curvature C, away from the focus f and away from the vertex in the concave part Trace the rays and obtain the image and draw it this will be point i (distance between the vertex and the image) Verify that the value of i (where the image is) by measuring directly with a ruler from the vertex to the point i, and compare it using the Descartes equation 1/f = 1/i+1/0 where i is the position or distance of the image measured from the vertex and that in this problem is the unknown to find. or, is the position of the object measured from the vertex and f is the position or distance of the focus measured from the vertex. Determine the magnification A using A = -1/0, and compare it to what the little arrow of the obtained image measures directly, (remember that the negative values indicate that the image is inverted) B. Make another circle 8 cm in diameter and now place or graph the arrow (the object) between C and F, that is, between the center of curvature and the focus. Calculate the position of the image directly with a ruler, as well as calculate it using Descartes' equation to compare if the results give the same or approximate. Also proceed to find and compare the values of the increase as in part A. C. Make another circle of 8 cm in diameter and locate the object, that is, the arrow between the focus and the vertex and find the image again, calculate with the rule how far the image is from the vertex, this is the value of i, then compare it with Descartes's equation 1/f = 1/i +1 / 0 to find the value of i again. Finally, calculate directly whether the image of the arrow increases or not, directly measure the size of the arrow with the ruler and compare it by obtaining it from the formula A = -1 /0, where i is the distance from the vertical to the image, i is the distance from vertex to object.