(a) Explicit with satisfying the stabiltiy condition 1.5 t=0 0.2 t=0.4 -0.6 -t=0.8 = 1 0.5 Numerical solution for u(x.t)
Posted: Mon May 02, 2022 4:23 pm
- A Explicit With Satisfying The Stabiltiy Condition 1 5 T 0 0 2 T 0 4 0 6 T 0 8 1 0 5 Numerical Solution For U X T 1 (28.05 KiB) Viewed 26 times
- A Explicit With Satisfying The Stabiltiy Condition 1 5 T 0 0 2 T 0 4 0 6 T 0 8 1 0 5 Numerical Solution For U X T 2 (22 KiB) Viewed 26 times
- A Explicit With Satisfying The Stabiltiy Condition 1 5 T 0 0 2 T 0 4 0 6 T 0 8 1 0 5 Numerical Solution For U X T 3 (26.71 KiB) Viewed 26 times
- A Explicit With Satisfying The Stabiltiy Condition 1 5 T 0 0 2 T 0 4 0 6 T 0 8 1 0 5 Numerical Solution For U X T 4 (27.41 KiB) Viewed 26 times
1033 Explicit without satisfying the stabiltiy condition (a) 3 t=0 20.2 t=0.4 -0.6 t=0.8 = 1 Numerical solution for u(x.t) 0 -1 -2 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 X
Crank- Nicholson scheme A<1/2 (a) a 0.9 0.8 0.7 0.6 Numerical solution for u(x,t) 0.5 0.4 0.3 t=0 t=0.2 t=0.4 t=0.6 -0.8 31 0.2 0.1 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 X
Crank- Nicholson scheme />1/2 (C) 5 .5 t=0 -0.2 t=0.4 -0.6 -t=0.8 = 1 0.5 Numerical solution for u(x.t) -0.5 -1 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 X