Answer Happy

can you solve this question and explain how did you solve it?
Consider a conductor in the shape of spherical shell with inner radius a and outer radius b. The current I is fed into the conductor at the inner surface with radius r = a. The current then flows within the conductor with a spherically symmetric flow in the radially outward direction. In other words, the current density within the conductor is J = Jf where the radial component J depends only on the radial coordinate r. The current is then collected at the outer surface at radius r = b. Let p be the resistivity of the conductor. You are going to compute the resistance R of the conductor after a few steps. (a) Find the radial component of the current density, J, for a point within the conductor that has radial coordinater (within the conductor means a <r<b). J = (b) Let E denote the radial component of the electric field. Find E as a function of r. E (C) Find the potential difference, V = V(a) – V(b), between the inner and the outer surfaces of the conductor. V = (d) What is the resistance R of the spherical conductor? R= Check