Answer Happy

Give ALL your answers correct to 4 d.p. Include minus sign in your answers where necessary. A load of 15 MW, with power factor 0.75 lagging, is supplied at a voltage level of 11 kV. The impedance of the line between the point of common coupling (PCC) and the load connection point is Z = (0.4+j0.9) 1. Power factor of the load is further improved to 1 (unity power factor operation) by adding the reactive power compensator at the load connection point. Part A) Calculate the current, impedance drop, and sending end voltage, before power factor correction [7 marks]: Current, I = Number Number A Impedance drop, AU = Number Number V Sending end voltage, IEI = Number Number V Part B) Determine the current, impedance drop, and sending end voltage, after power factor correction [7 marks]: Current, I = Number Number A Impedance drop, AV = Number Number V Sending end voltage, E = Number Number V Part C) Find the voltage drop for parts a) and b) above, as well as the corresponding power factor at the PCC. [6 marks] Parta: Voltage drop, IAV I= Number V power factor, Number Part b: Voltage drop, IAVI = Number V power factor, Number