Answer Happy

A load of 12 MW, with power factor 0.8 lagging, is supplied at a voltage level of 11 kV. The impedance of the line between the point of common coupling (PCC) and the load connection point is Z = (0.4+j0.9) 2. Power factor of the load is further improved to 1 (unity power factor operation) by adding the reactive power compensator at the load connection point Part A) Calculate the current, impedance drop, and sending end voltage, before power factor correction Current, I = L A Impedance drop, AU = L V Sending end voltage, 1E| = L V Part B) Determine the current, impedance drop, and sending end voltage, after power factor correction Current, I = 2 *A Impedance drop, AU = 2 Sending end voltage, E = 2 .V V Part C) Find the voltage drop for parts a) and b) above, as well as the corresponding power factor at the PCC. Parta: Voltage drop, AV= Part b: Voltage drop, IAVI = V power factor = V power factor = .