thanks in advance

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thanks in advance

Thanks In Advance 1 (49.95 KiB) Viewed 30 times

A load of 12 MW, with power factor 0.8 lagging, is supplied at a voltage level of 11 kV. The impedance of the line between the point of common coupling (PCC) and the load connection point is Z = (0.4+0.9) 2 Power factor of the load is further improved to 1 (unity power factor operation) by adding the reactive power compensator at the load connection point Part A) Calculate the current, impedance drop, and sending end voltage, before power factor correction [7 marks]: Current, I = Number Number A Impedance drop, AU = Number Number Sending end voltage, E|- Number Number *A Part B) Determine the current, impedance drop, and sending end voltage, after power factor correction (7 marks] Current, I = Number Number Impedance drop, AU = Number 2 Number Sending end voltage, E = Number 2 Number "V Part C) Find the voltage drop for parts a) and b) above, as well as the corresponding power factor at the PCC, 16 marks) Parta: Voltage drop. AV = Number V power factor, Number Part b: Voltage drop. AV = Number V power factor, Number