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Give ALL your answers correct to 4 d.p. Include minus sign in your answers where necessary. A load of 18 MW, with power factor 0.8 lagging, is supplied at a voltage level of 11 kV The impedance of the line between the point of common coupling (PCC) and the load connection point is Z = (0.4+0.9) 12 Power factor of the load is further improved to 1 (unity power factor operation) by adding the reactive power compensator at the load connection point A Part A) Calculate the current, impedance drop, and sending end voltage, before power factor correction [7 marks] Current, 1 = Number Number Impedance drop, AU = Number 2 Number "V Sending end voltage IEL = Number Z Number "V Part B) Determine the current impedance drop and sending end voltage, after power factor correction 17 marks) Current, I = Number Number "A Impedance drop. AU = Number Number "V Sending end voltage E = Number 2 Number V Part C) Find the voltage drop for parts a) and b) above as well as the corresponding power factor at the PCC [6 marks) Part a Voltage drop. 4V = Numbe V power factor Norber Part b Voltage drop AVI = Nome V power factoriimter