2.148. Think of the current voltage conversion circuit in Fig. P2.148(a). Figure P shows this circuit by selecting the c

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2 148 Think Of The Current Voltage Conversion Circuit In Fig P2 148 A Figure P Shows This Circuit By Selecting The C 1 (103.84 KiB) Viewed 32 times

2.148. Think of the current voltage conversion circuit in Fig. P2.148(a). Figure P shows this circuit by selecting the correct frequency for Vin It can be made similar to the characteristics of the inductor circuit of 2.148(b). Since inductors with almost ideal characteristics are difficult to produce and are more expensive than operational amplifier circuits with the same characteristics, it is often desirable to use these circuits rather than actual inductors. (a) It is assumed that the open loop response of the operational amplifier can be expressed as A(jw) = Ao = /(1+jw/wp) A A0/(1 +if/f). Find Voul's expression with the scent of Vin. Note that = Vin drives the v-terminal without series resistance. (b) Find the expression for the current I, flowing through Ri. (c) Using the answer to question (b), find the expression for complex impedance Zin = Vin 11, as viewed from the input terminal of the circuit. (d) It is assumed that the frequency w < Aow, of Vin lies in the region. Find the resistance value of the equivalent inductance in Figure P2. 148(b) at this frequency limit. (e) Find Lea and Reg values when R1 = 2018 and the open loop rohm parameter of the operational amplifier is 10 = 105 and fo = 4 Hz.
RI ww Leg Reg w Zin> Vout = Vin Come on. + (b) Figure P2.148