For the beam shown below, F = 70 kN and L=6 m. E = 200 GPa, I = 8 x 10 mm. Consider bending strain energy only: a) Deter

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answerhappygod
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For the beam shown below, F = 70 kN and L=6 m. E = 200 GPa, I = 8 x 10 mm. Consider bending strain energy only: a) Deter

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For The Beam Shown Below F 70 Kn And L 6 M E 200 Gpa I 8 X 10 Mm Consider Bending Strain Energy Only A Deter 1
For The Beam Shown Below F 70 Kn And L 6 M E 200 Gpa I 8 X 10 Mm Consider Bending Strain Energy Only A Deter 1 (55.72 KiB) Viewed 37 times
For the beam shown below, F = 70 kN and L=6 m. E = 200 GPa, I = 8 x 10 mm. Consider bending strain energy only: a) Determine the displacement at the end A. b) Determine the slope at the end A. (please assume an anticlockwise direction for M;) c) Determine the deformed shape, shear force, and bending moment diagrams of the beam. F 15 kN/m B с than 18 m Part a) Task 1: At which point does the imaginary load por moment M; apply? OA OB OC Part a) Task 2: To determine displacement should you apply an imaginary load Por moment M;? O Load P O Moment M; Part a) Task 3: Determine vertical reactions as a function of P (actual values, assuming upward reactions. RB- P+ RC= P+
Part a) Task 4: Xi is for member AB (Make a cut between A and B, and use LH freebody). X2 is for member BC (Make a cut between B and C, and use LH freebody). Actual M (when P= Member Origin Limits M (kNm) (assuming anticlockwise direction, fill in with actual values OM OP 0 xi? + AB A x 2 + PX X1 Xi X22+ X2 + X2 + BC B PX2 + P + X2 + I Submit part Unanswered Parta) Task 5: After integration is completed, The first term in the numerator for AB is The second term in the numerator for BC is Convert the number in the numerator into Nmm by 10_ Submit part Unanswered
Part a) Task 6: Vertical displacement at A (mm) (absolute value: Part b) Task 1: At which point does the imaginary load P or moment M; apply? OA ов ос Part b) Task 2: To determine slope, should you apply an imaginary load P or moment M;? O Load P O Moment M Part b) Task 3: Determine vertical reactions as a function of M; (actual values, assuming upward reactions). RB- M; + RC= Mi+ +
Part b) Task 4: Xi is for member AB (Make a cut between A and B, and use LH freebody). X2 is for member BC (Make a cut between B and C, and use LH freebody). Member Actual M (when Mj= Origin M(kNm) (assuming anticlockwise direction, fill in with actual values Limits ам OM; 0- x+ AB А x12 X1 + M X1 0- x2? + X2 + X2M; + M; + BC B X2 + Submit part Unanswered Part b) Task 5: After integration is completed, The first term in the numerator for AB is The second term in the numerator for BC is Convert the number in the numerator into Nmm² by 10 Submit part Unanswered
Part b) Task 6: Slope at A (rad) (absolute value: - 6 Part c) Task 1: Deformed shape of the beam: o o 0
Part c) Task 2: Shear force diagram of the beam: o 0 o
Part c) Task 2: What is the maximum shear force to the left of B (absolute value? KN Part c) Task 3: Bending moment diagram of the beam: o 0 o o o
Part c) Task 3: What is the maximum moment at B(absolue value? kNm What is the maximum moment between B and C (absolute value)? kNm What distance to the left of C does the maximum moment between B and Coccur? What distance to the right of B does the contraflexure point occur? m m
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