- 0 15 15 15 15 8 12opef Cu 1000psf Sat 15 Cg Clay 5 5 C6 10 7 5 15 5 Rs 8 10 Tau For Geosynthehs Is 20 1 (235.96 KiB) Viewed 28 times
(0,15) 15 (15,15) 8 = 12opef Cu = 1000psf Sat 15 CG CLAY (5,5) C6 (10,7-5) *** (15,5) RS 8-10° Tau for geosynthehs is 20
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(0,15) 15 (15,15) 8 = 12opef Cu = 1000psf Sat 15 CG CLAY (5,5) C6 (10,7-5) *** (15,5) RS 8-10° Tau for geosynthehs is 20
(0,15) 15 (15,15) 8 = 12opef Cu = 1000psf Sat 15 CG CLAY (5,5) C6 (10,7-5) *** (15,5) RS 8-10° Tau for geosynthehs is 20004lft (0,0) Question 1 A geotextile reinforced slope is shown. The drawing is to scale. X and Y coordinates are given and all length units are in feet. For the circular failure surface shown in the figure, find the factor of safety against instability. Conduct an undrained analysis. Use the center of gravity (CG) of the area enclosed by the circular failure surface shown in the figure. The reinforcement intersects the circular failure surface at coordinate (10.6,5). The soil and geotextile information is shown in the figure. The geotextile reinforcement used is 10 feet long. Calculate the factor of safety against failure on the failure surface shown above, with and without the geosynthetic. If any assumptions are made, be sure to clearly state them and justify them. Note the soil is saturated clay. (40 pts)
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