Practice problem - serviceability 200 mm (a) Find the neutral axis and the second moment of area of the given RC section

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Practice problem - serviceability 200 mm (a) Find the neutral axis and the second moment of area of the given RC section

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Practice Problem Serviceability 200 Mm A Find The Neutral Axis And The Second Moment Of Area Of The Given Rc Section 1
Practice Problem Serviceability 200 Mm A Find The Neutral Axis And The Second Moment Of Area Of The Given Rc Section 1 (48.61 KiB) Viewed 36 times
Practice Problem Serviceability 200 Mm A Find The Neutral Axis And The Second Moment Of Area Of The Given Rc Section 2
Practice Problem Serviceability 200 Mm A Find The Neutral Axis And The Second Moment Of Area Of The Given Rc Section 2 (52.33 KiB) Viewed 36 times
Practice problem - serviceability 200 mm (a) Find the neutral axis and the second moment of area of the given RC section with the following properties: f = 32 MPa E = 30,100 MPa E, = 200,000 MPa 500 450 3N16 (b) Find the second moment of area of the cracked section for the section given in part (a). Note: case (1) Ignore the reinforcing steel, 1, = 2083 * 106 mm case (ii) Include the reinforcing steel using transformed section method, Given: 1, = 2214.9 * 106 mm Icr = 544 * 106 mm Tutorial
2000 W 3N16 (b) Find the second moment of area of the cracked section for the section given in part (a). Note: case (1) Ignore the reinforcing steel, I, = 2083 * 106 mm case (ii) Include the reinforcing steel using transformed section method, Given: I, = 2214.9 * 106 mm I = 544 106 mm Tutorial Practice problem - serviceability (c) Calculate the short-term and long-term deflections at the mid-span of beam AB for th proposex beam shown below and assess the proposed beam AB for maximum allowable deflection of span/250 requirement. Take the beam as being simply supported by reinforces concrete pier at supported. The beam is doubly reinforced T-section with dimensions and reinforcement shown for the positive and negative moment regions of the beam. Loading: Superimposed permanent load, SDL = 15 kN/m Imposed load, Q = 30 kN/m Given: f'.- 40 MPa the Unit weight of RC = 25 kN/m V = 0.7 =0.4 **=600 - 10
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