Given a derivative transform of SBY (s) – sạy (0) - sy (0) - 7" (0) - 3sY (s) – 3sy (0) - 3y (0) +Y (s) + 3 = 0 What is

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Given a derivative transform of SBY (s) – sạy (0) - sy (0) - 7" (0) - 3sY (s) – 3sy (0) - 3y (0) +Y (s) + 3 = 0 What is the differential equation? O 3y" - 37" + y +2 = 0 O 34" - 34' + y + 2y = 0 Oy - 3y" + y + 2y = 0 OY" - 34" + y +2 = 0 Oy" - "' + y +2 = 0 Oy" - 3y + y +2 = 0
Using the definition of Laplace transform, what is the equivalent integral if f(t) = 5t? = о о -st $2 st -sť o test to jest o & + o te- se- 0 -te-st-est o test o - test 5 $2
Using the definition of Laplace transform, what is the equivalent integral if f(t) = e3t? O-3 1 e-(3-3)t 3-3 - o els-3) O 8-3 o og e-(+3) s+3t O 3+3 O 1els+3) s+3 O e-(-3) 8-3 O-te-(+3) 33 s+3
Find the laplace transform of f(t) = 2t4 - 3e3+ + 10 cos 2t OF(s) 757-209-2095_4898+9652 +1925-384 38 - 287+1636-83 O F(s) = 787–2006 – 12.4 +4888 –19252 +963–384 98-287 +1689 -85 O F(s) = 737-2096-1285-4894-968--965-384 38 -237 +1686-88 787-2080-128-488-9252 +1965-384 O F(3) = $8-287+1656-83 OF(s) 757-2096-12086 +4888-92s? +1965-384 38-287+1684-88 OF(s) 787-2086–12s4 +4889-9582 +1928-384 38 -287-1686-835 F(s) = 787-20564-12-9689 +48 +1925-384 38-257 +1685-83 O F(s) 787-2080-1284 +4858-963 +1925-384 38-28T+1656--83
Find the laplace transform of f(t) = tetsin 2t OF(s) 649 28 (91-45+8) + 12 (92-48+8) (32-4s+8) O F(s) = 102-45+8) + 28 12 48 (32-45+8) (52-45+8) OF(s) = (02-43+8) 2s+8 64 + (32-4s+8) OF(s) = (32 -45+8) 2s 64 + 12s+2 (32-45+8) (32-4s+8) O F($) = 125+2 (x2 - 4s+8) 48 (52-4s+8) 48 OF(8) 128+2 (32–4s+8) (2-4s+8) O F(8) 12 (52-45+8) 64 (s2 - 4s+8) OF(s) 2s (82-45+8) 8) + 2 (32-4s+8) 36 (32-4s+8)
260 +2 0-0 29 -90 + + 282 2 + 2 - 2 2 - 0 78 – 2 / 3 + 2 1 - 0 26 2 / + - 2 1 1 - 0 26 2 / - - 2 2 - 0 16-03 +24-0 26 2 2 2 2 2 2 2 - 0 -9t 52-88-9 s+3 Find the inverse laplace of
Find the inverse laplace of F(s) (s2+a%)(2+) consider a? #62, ab = 0 O f(t) a sin at+b sin bt O f(t) cos at-cost 2²-g² O f(t) cos at+cos bt O f(t) a sin at-b sin bt o f(t) b sin at-o sin ut ab[62-02) o f(t) = b sin atta sin bt ab (6²²)
Find the Laplace Transformation of y" +3y + 2y = 4e-32 when y(0) = 2, y (0) = 4 OY(s) = 282-163+32 +692 +118+6 O Y (8) 262 +168+30 34 +682 +125+6 O Y (8) = 28° +125-34 34 +682 +118+6 O Y(s) = 282 +16s+32 33 +6824125+6 OY(s) 2524-128 +34 31 +682 +12s+6 O Y(s) = 252 +148 +34 3° +6° +12s+6 O Y(s) = 161 +113+6 2:2 +168 +34 OY(s) = 282 +68+34 *+689 +125+6