1. The Ke for the reaction below is 2.31x10 at equilibrium at 400 C. 21Bc () 11 12+ Bryce) H=-237 KJ/mol 1 What is the e
-
answerhappygod
- Site Admin
- Posts: 899604
- Joined: Mon Aug 02, 2021 8:13 am
1. The Ke for the reaction below is 2.31x10 at equilibrium at 400 C. 21Bc () 11 12+ Bryce) H=-237 KJ/mol 1 What is the e
1. The Ke for the reaction below is 2.31x10 at equilibrium at 400 C. 21Bc () 11 12+ Bryce) H=-237 KJ/mol 1 What is the equilibrium concentration of 12 and Bry, if the equilibrium Concentration of IBr is 0.0986 M 2 marks
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!