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1. The Kc for the reaction below is 9.34 x 10-5 at equilibrium at 500 K: 21Br (8) 12 (g) + Br2 (g). H=-578 KJ/mol 1. Wha

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1. The Kc for the reaction below is 9.34 x 10-5 at equilibrium at 500 K: 21Br (8) 12 (g) + Br2 (g). H=-578 KJ/mol 1. Wha

Posted: Fri Apr 29, 2022 2:00 pm
by answerhappygod
1 The Kc For The Reaction Below Is 9 34 X 10 5 At Equilibrium At 500 K 21br 8 12 G Br2 G H 578 Kj Mol 1 Wha 1
1 The Kc For The Reaction Below Is 9 34 X 10 5 At Equilibrium At 500 K 21br 8 12 G Br2 G H 578 Kj Mol 1 Wha 1 (12.51 KiB) Viewed 36 times
1. The Kc for the reaction below is 9.34 x 10-5 at equilibrium at 500 K: 21Br (8) 12 (g) + Br2 (g). H=-578 KJ/mol 1. What is the equilibrium concentration of 12 and Brą, if the equilibrium Concentration of IBr is 0.0105 M. 2 marks
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