- 1 The Kc For The Reaction Below Is 9 34 X 10 5 At Equilibrium At 500 K 21br 8 12 G Br2 G H 578 Kj Mol 1 Wha 1 (12.51 KiB) Viewed 34 times
1. The Kc for the reaction below is 9.34 x 10-5 at equilibrium at 500 K: 21Br (8) 12 (g) + Br2 (g). H=-578 KJ/mol 1. Wha
-
answerhappygod
- Site Admin
- Posts: 899604
- Joined: Mon Aug 02, 2021 8:13 am
1. The Kc for the reaction below is 9.34 x 10-5 at equilibrium at 500 K: 21Br (8) 12 (g) + Br2 (g). H=-578 KJ/mol 1. Wha
1. The Kc for the reaction below is 9.34 x 10-5 at equilibrium at 500 K: 21Br (8) 12 (g) + Br2 (g). H=-578 KJ/mol 1. What is the equilibrium concentration of 12 and Brą, if the equilibrium Concentration of IBr is 0.0105 M. 2 marks
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!