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If 49.6 mL of lead(II) nitrate solution reacts completely with excess sodium iodide solution to yield 0.382 g of the pre

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If 49.6 mL of lead(II) nitrate solution reacts completely with excess sodium iodide solution to yield 0.382 g of the pre

Posted: Fri Apr 29, 2022 1:51 pm
by answerhappygod
If 49 6 Ml Of Lead Ii Nitrate Solution Reacts Completely With Excess Sodium Iodide Solution To Yield 0 382 G Of The Pre 1
If 49 6 Ml Of Lead Ii Nitrate Solution Reacts Completely With Excess Sodium Iodide Solution To Yield 0 382 G Of The Pre 1 (11.04 KiB) Viewed 35 times
If 49.6 mL of lead(II) nitrate solution reacts completely with excess sodium iodide solution to yield 0.382 g of the precipitate lead(II) iodide, what is the molarity of lead(II)ion in the original solution?
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