a 1. Which solute would provide the sharper end point in a titration with HCl: a. (5 points) 0.10 M NH3 (Ka= 5.7 x 10-10
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a 1. Which solute would provide the sharper end point in a titration with HCl: a. (5 points) 0.10 M NH3 (Ka= 5.7 x 10-10
a 1. Which solute would provide the sharper end point in a titration with HCl: a. (5 points) 0.10 M NH3 (Ka= 5.7 x 10-10) or 0.10 M sodium phenolate (Ka=1 x 10-10)? Explain. == = = b. (5 points) 0.10 M methylamine (Ka=2.3 x 10-11) or 0.10 M hydroxylamine (Ka=1.1 x 10-6)? Explain.(10 points)
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