2- The directions tell you to add 102 mg of methyl benzoate (MW=136 g/mole) into a 5-mL conical vial. Separately, 0.20 m

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2- The directions tell you to add 102 mg of methyl benzoate (MW=136 g/mole) into a 5-mL conical vial. Separately, 0.20 m

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2 The Directions Tell You To Add 102 Mg Of Methyl Benzoate Mw 136 G Mole Into A 5 Ml Conical Vial Separately 0 20 M 1
2 The Directions Tell You To Add 102 Mg Of Methyl Benzoate Mw 136 G Mole Into A 5 Ml Conical Vial Separately 0 20 M 1 (44.32 KiB) Viewed 14 times
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2- The directions tell you to add 102 mg of methyl benzoate (MW=136 g/mole) into a 5-mL conical vial. Separately, 0.20 mL of conc. sulphuric acid, (d=1.84g/ml, MM=98g/mol) and 0.080 mL of conc. Nitric acid (d=1.42g/ml, and MM=63g/ml) are put in a vial to form the nitrating mixture. Determine the limiting reactant. How many moles would be the product?
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